By using the subsitution/elimination method...
A florist will make up bouquets of different flowers. The rates and bouquets are listed below. If the flowers cost the same individually or in a bouquet, how much does one orchid cost?
Small bouquet:
2 snapdragons, 1 rose, 1 orchid $8
Medium bouquet:
5 snapdragons, 3 roses, 2 orchids $19
Large bouquet:
8 snapdragons, 5 roses, 5 orchids $38
Ah, I'd really appreciate the clarification! It's a study question of mine and I'm a bit confused..
How do you solve this?
If we let s = snapdragons, r = roses and o = orchids, then:
Small bouquet: 2s + r + o = 8
Medium bouquet: 5s + 3r + 2o = 19
Large bouquet: 8s + 5r + 5o = 38
From 1)
o = 8 - r - 2s
Substituting into 3)
8s + 5r + 5(8-r-2s) = 38
8s + 5r + 40 - 5r - 10s = 38
-2s = -2
s = 1
We can now solve the first two simultaneously.
2 + r + o = 8
r + o = 6
o = 6 - r
5 + 3r + 2o = 19
3r + 2(6-r) = 14
3r + 12 - 2r = 14
r = 2
Finally, this lets us solve for o:
o = 6 - r
= 4
So, the snapdragons cost $1 each, the roses $2 each, and the orchids $4 each.
You have to be careful picking your substitutions - the only reason this substitution cancelled so well was because I saw that the ratio of roses:orchids in the final question was 1:1, and I knew that by making o the subject of the first equation, I would cancel out the roses in the final equation. It's a skill you learn by practice...
You will learn about matrices some day, which makes these sort of questions a lot easier.
Reply:i have problem with that kind of question too
but i don`t know how to solve it so sorry
Tuesday, January 24, 2012
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